Let T : ℝn → ℝn be a linear transform and A be the square matrix defined so that T(x) = Ax. Then the absolute value of the determinant of A, denoted det(A), measures the change in volume under T. This means that if S is a shape of volume V then T(S) = {T(s) : s ∈ ℝn} has volume |det (A)|V.
Definition: For any n ∈ ℕ, The determinant is the unique function from the set of square matrices of size n so the real numbers with the following 3 properties:
The determinant of a linear transform T : ℝn → ℝn is the determinant of its associated matrix.
Properties:
Computation: There is a thing called cofactor expansion. It is terrible but we will learn it. In practice, another method is used like LU-decomposition. There LU decompositon of a matrix A is A = LU where L is lower trianguluar and U is upper triangular. Then det (A) = det (L)det (U), where det (L) and det (U) is the product of the diagonal. Give n = 2 and n = 3 shortcuts and the general cofactor formula. Note that you can expand along any row or column.
Notation: Often you denote the determinant of a matrix by replacing the square brackets by straight lines.
Examples: Compute the determinant in the following cases:
Theorem: Let S = {a1, …, an} be a set of vectors in ℝn, let A = [a1 … an] and T : ℝn → ℝn be given by T(x) = Ax. Then the following are equivalent:
tldr: Determinant tells you about change of volume. It is a test of invertibility.