Consider the following maps of polynomials \(S:\mathcal{P}\rightarrow\mathcal{P}\) and \(T:\mathcal{P}\rightarrow\mathcal{P}\) defined by

\[ S(g(x))= 4 \, g\left(-2\right) - 2 \, g'\left(-4\right) \hspace{1em} \text{and} \hspace{1em} T(g(x))= 3 \, g'\left(x\right) - 4 \]

Explain why one these maps is a linear transformation and why the other map is not.

Answer:

\(S\) is linear and \(T\) is not linear.