Explain how to find the general solution to the given ODE, and the particular solution to the given IVP.
\[ -4 \, {y} = -2 \, {y'} ,\hspace{1em} y\big( \log\left(3\right) \big)= -18 \]
Then show how to verify that your particular solution is correct.
Answer:
\[ {y} = k e^{\left(2 \, t\right)} \]
\[ {y} = -2 \, e^{\left(2 \, t\right)} \]