Find the solution to the given IVP.
\[ 2 \, {y} {\left(4 \, t - 1\right)} + 2 \, {y'} = 0 \hspace{2em} y( 0 )= -2 \, e^{2} \]
Answer:
\[ {y} = -2 \, e^{\left(-2 \, t^{2} + t + 2\right)} \]