Find the solution to the given IVP.
\[ -3 \, {y'} {y} = -\frac{12 \, t}{{y}^{2}} - \frac{3}{{y}^{2}} \hspace{2em} y( 2 )= 3 \]
Answer:
\[ {y} = {\left(2 \, t^{2} + t + 17\right)}^{\frac{1}{3}} \]