Find the solution to the given system of IVPs.
\[ 2 \, {x} + {x'} = -3 \, {y} \hspace{2em}x(0)= 4 \]
\[ -3 \, {y} + {y'} = -12 \, {x} \hspace{2em}x(0)= 1 \]
Answer:
\[x= e^{\left(7 \, t\right)} + 3 \, e^{\left(-6 \, t\right)} \]
\[y= -3 \, e^{\left(7 \, t\right)} + 4 \, e^{\left(-6 \, t\right)} \]