Find the solution to the given system of IVPs.
\[ -{y} = {x'} + {x} \hspace{2em}x(0)= 0 \]
\[ 0 = 4 \, {x} - 6 \, {y} - {y'} \hspace{2em}x(0)= -3 \]
Answer:
\[x= e^{\left(-2 \, t\right)} - e^{\left(-5 \, t\right)} \]
\[y= e^{\left(-2 \, t\right)} - 4 \, e^{\left(-5 \, t\right)} \]