Find the solution to the given system of IVPs.
\[ {y} = {x'} + 2 \, {x} \hspace{2em}x(0)= -2 \]
\[ -4 \, {x} = {y'} - 3 \, {y} \hspace{2em}x(0)= -5 \]
Answer:
\[x= -e^{\left(2 \, t\right)} - e^{\left(-t\right)} \]
\[y= -4 \, e^{\left(2 \, t\right)} - e^{\left(-t\right)} \]