Find the solution to the given system of IVPs.

\[ 2 \, {y} = -4 \, {x} + {x'} \hspace{2em}x(0)= -1 \]

\[ -2 \, {x} = -9 \, {y} + {y'} \hspace{2em}x(0)= 1 \]

Answer:

\[x= e^{\left(8 \, t\right)} - 2 \, e^{\left(5 \, t\right)} \]

\[y= 2 \, e^{\left(8 \, t\right)} - e^{\left(5 \, t\right)} \]