Find the solution to the given system of IVPs.
\[ {x'} - {x} = 3 \, {y} \hspace{2em}x(0)= -2 \]
\[ -12 \, {x} = -4 \, {y} - {y'} \hspace{2em}x(0)= -7 \]
Answer:
\[x= -3 \, e^{\left(5 \, t\right)} + e^{\left(-8 \, t\right)} \]
\[y= -4 \, e^{\left(5 \, t\right)} - 3 \, e^{\left(-8 \, t\right)} \]