Find the solution to the given system of IVPs.
\[ 0 = {x} + {x'} + 4 \, {y} \hspace{2em}x(0)= 5 \]
\[ -{x} + 2 \, {y} = {y'} \hspace{2em}x(0)= 0 \]
Answer:
\[x= e^{\left(3 \, t\right)} + 4 \, e^{\left(-2 \, t\right)} \]
\[y= -e^{\left(3 \, t\right)} + e^{\left(-2 \, t\right)} \]