Find the solution to the given system of IVPs.
\[ {x'} - {x} - 4 \, {y} = 0 \hspace{2em}x(0)= 3 \]
\[ 2 \, {y} = {x} - {y'} \hspace{2em}x(0)= 2 \]
Answer:
\[x= 4 \, e^{\left(2 \, t\right)} - e^{\left(-3 \, t\right)} \]
\[y= e^{\left(2 \, t\right)} + e^{\left(-3 \, t\right)} \]