Find the solution to the given system of IVPs.

\[ {y} = -{x'} - 4 \, {x} \hspace{2em}x(0)= -2 \]

\[ 0 = -9 \, {y} - {y'} + 4 \, {x} \hspace{2em}x(0)= -5 \]

Answer:

\[x= -e^{\left(-5 \, t\right)} - e^{\left(-8 \, t\right)} \]

\[y= -e^{\left(-5 \, t\right)} - 4 \, e^{\left(-8 \, t\right)} \]