Find the solution to the given system of IVPs.
\[ 0 = {x} - {x'} + 4 \, {y} \hspace{2em}x(0)= -3 \]
\[ -{y'} = -{x} + 2 \, {y} \hspace{2em}x(0)= -2 \]
Answer:
\[x= -4 \, e^{\left(2 \, t\right)} + e^{\left(-3 \, t\right)} \]
\[y= -e^{\left(2 \, t\right)} - e^{\left(-3 \, t\right)} \]