Find the solution to the given system of IVPs.
\[ -{x'} = -3 \, {x} + 9 \, {y} \hspace{2em}x(0)= -10 \]
\[ -4 \, {x} - 2 \, {y} = {y'} \hspace{2em}x(0)= 3 \]
Answer:
\[x= -9 \, e^{\left(7 \, t\right)} - e^{\left(-6 \, t\right)} \]
\[y= 4 \, e^{\left(7 \, t\right)} - e^{\left(-6 \, t\right)} \]