From the resistivity of copper, and from the wire dimensions in the AWG table, confirm the resistance of 12-gauge copper wire, in ohms per kilometer, that is listed in the table. Show your work, which will include unit conversions. Assume room temperature.
Hint: if you find the resistance of a 1000 meter length of wire, you will have found the ohms per kilometer.
Strategy:
Resistance = ResistivityLength / Cross-Sectional Area, or $$ R = \frac {\rhoL}{A} $$
Final units should look like this: $$\Omega = \frac{ \Omega m}{m^2} * 1000meters$$
Given from Wiki articles :
$16.78 n\Omega m$ = 1.678e-8$\Omega m$
Electrical resistivities of the Elements: https://en.wikipedia.org/wiki/Electrical_resistivities_of_the_elements_%28data_page%29
to convert from $ 1mm^2 $ to $ 1m^2 $ simply square both sides of the fundamental conversion: $ 1mm = \frac{1m}{1e3mm}$
$ 3.31mm^2$ = 3.31e-6$m^2$
12 Gauge Copper wire:https://en.wikipedia.org/wiki/American_wire_gauge
$$ Resistance = \frac{\rho}{Crosssectional Area} * Length $$$$ \Omega = \frac{1.678e-8\Omega m}{3.31e-6 m^2} * 1000m = 5.07 $$This is the resistance of a 1000m 12gauge copper wire, it can be seen that this is also the resistance/Km
Resistivity_nOhmm = 16.78
Resistivity_Ohmm = Resistivity_nOhmm * (1 / 1e9)
Area_sqrmm = 3.31
Area_sqrm = Area_sqrmm * (1/1e6)
Length = 1000
Q1 = Resistivity_Ohmm/Area_sqrm * Length
Q1
print('{:0.2f}'.format(Q1))
This answer closely approximates the Resistivity of Copper Wire given at $ 5.211 \frac{m \Omega}{m} $.
https://en.wikipedia.org/wiki/American_wire_gauge
note: $ \frac{m \Omega}{m} = \frac{\Omega}{Km} $
Calculate the resistance of 12 AWG aluminum wire in ohms/km at room temperature. Why is copper preferred over aluminum conductor, even though it is more expensive?
Same Strategy as Question1. Only, there's a different resistivity.
Wiki-provided ( $\rho$ ) and Area:
Resistivity = 2.65e-8
Area = 3.31e-6
Q2 = (Resistivity/Area) *1000
print('{:0.2f}'.format(Q2))
Aluminum has a Resistance of ~8 $\Omega$/Km
As we all know, electricty is tranmitted over a certain distance before it can be used.
For the purposes of transmitting electrical energy effieciently, resistance is a bad thing. Resistance causes some of the energy to be converted into heat.
The total cost comparison between the initial investment of copper and the long-term energy cost of aluminum, makes copper the more cost-effective conductor.
| Material | Cost | Density |
|---|---|---|
| Copper | $\frac{$4.75}{Kg}$ | $\frac{8.96 \cdot 10^3 Kg}{m^3}$ |
| Aluminum | $\frac{$1.73}{Kg} $ | $\frac{2.7 \cdot 10^3 Kg}{m^3} $ |
You can get up to date prices at the London Metal Exchange. But please use the values above.
Using the Costs and Densities given above, Calculate the raw material cost per meter for 12 AWG wire in both copper and aluminum.
How does this compare to the cost of wire you can find online?
hint: Density * Volume = Mass
Volume of 1m of 12 gauge wire: ~cylinder = $ CrossSectional Area * Length = Volume $
Area from previous problems = 3.31e-3 $m^2$
3.31e-6 $m^2$ $*$ 1m = 3.31e-6$m^3$ = Volume
Copper_Cost = 4.75
Copper_Density = 8.96e3
Volume_12AWG = 3.31e-6 * 1
Copper_CostPerLength = Copper_Cost * Copper_Density * Volume_12AWG
print('{:0.2f}'.format(Copper_CostPerLength))
This calulation approximates the cost of 12-gauge copper wire to be 14 cents per meter
This product from Home Depot is 2 conductors of 12 gauge copper wire and is 47 USD for 250 ft. We approximate as 0.20 cents per foot or 0.60 cents per meter. It looks like the raw copper cost is about 50% of this cost.
Aluminum_Cost = 1.73
Aluminum_Density = 2.7e3
Volume_12AWG = 3.31e-6
Aluminum_CostPerLength = Aluminum_Cost * Aluminum_Density * Volume_12AWG
print('{:0.2f}'.format(Aluminum_CostPerLength))
The cost of 12-gauge aluminum wire is ~2 cents per meter