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Construction of conics
PROBLEM: Determine the equation of a conic if two tangents and three its points are given.
f == 0
a + d + f == 0
16*a + 12*b + 9*c + 4*d + 3*e + f == 0
[{x: 3*y - 1}]
[{x: 1/2*y + 2}]
9*a*y^2 + 3*b*y^2 + c*y^2 - 6*a*y - b*y + 3*d*y + e*y + a - d + f
-4*(a - d + f)*(9*a + 3*b + c) + (6*a + b - 3*d - e)^2
1/4*a*y^2 + 1/2*b*y^2 + c*y^2 + 2*a*y + 2*b*y + 1/2*d*y + e*y + 4*a + 2*d + f
-(a + 2*b + 4*c)*(4*a + 2*d + f) + 1/4*(4*a + 4*b + d + 2*e)^2
[{f: 0, b: -13/9*e, a: 2/3*e, d: -2/3*e, c: 19/27*e}, {f: 0, b: -21/17*e, a: 6/17*e, d: -6/17*e, c: 43/51*e}, {f: 0, b: -149/97*e, a: 54/97*e, d: -54/97*e, c: 283/291*e}, {f: 0, b: -7/11*e, a: 2/11*e, d: -2/11*e, c: 3/11*e}]
2/3*x^2 - 13/9*x*y + 19/27*y^2 - 2/3*x + y == 0
6/17*x^2 - 21/17*x*y + 43/51*y^2 - 6/17*x + y == 0
54/97*x^2 - 149/97*x*y + 283/291*y^2 - 54/97*x + y == 0
2/11*x^2 - 7/11*x*y + 3/11*y^2 - 2/11*x + y == 0