/* log1p(x) = log(1+x). The log1p function is designed to avoid the1significant loss of precision that arises from direct evaluation when x is2small. Use the substitute from _math.h on all platforms: it includes3workarounds for buggy handling of zeros.4*/56static double7_Py_log1p(double x)8{9/* Some platforms (e.g. MacOS X 10.8, see gh-59682) supply a log1p function10but don't respect the sign of zero: log1p(-0.0) gives 0.0 instead of11the correct result of -0.0.1213To save fiddling with configure tests and platform checks, we handle the14special case of zero input directly on all platforms.15*/16if (x == 0.0) {17return x;18}19else {20return log1p(x);21}22}2324#define m_log1p _Py_log1p252627