hash.c

/*-
 * SPDX-License-Identifier: BSD-4-Clause
 *
 * Copyright (c) 1995
 *	Bill Paul <[email protected]>.  All rights reserved.
 *
 * Redistribution and use in source and binary forms, with or without
 * modification, are permitted provided that the following conditions
 * are met:
 * 1. Redistributions of source code must retain the above copyright
 *    notice, this list of conditions and the following disclaimer.
 * 2. Redistributions in binary form must reproduce the above copyright
 *    notice, this list of conditions and the following disclaimer in the
 *    documentation and/or other materials provided with the distribution.
 * 3. All advertising materials mentioning features or use of this software
 *    must display the following acknowledgement:
 *	This product includes software developed by Bill Paul.
 * 4. Neither the name of the author nor the names of any co-contributors
 *    may be used to endorse or promote products derived from this software
 *    without specific prior written permission.
 *
 * THIS SOFTWARE IS PROVIDED BY Bill Paul AND CONTRIBUTORS ``AS IS'' AND
 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
 * ARE DISCLAIMED.  IN NO EVENT SHALL Bill Paul OR CONTRIBUTORS BE LIABLE
 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
 * SUCH DAMAGE.
 */

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#include "hash.h"

/*
 * This hash function is stolen directly from the
 * Berkeley DB package. It already exists inside libc, but
 * it's declared static which prevents us from calling it
 * from here.
 */
/*
 * OZ's original sdbm hash
 */
u_int32_t
hash(const void *keyarg, size_t len)
{
	const u_char *key;
	size_t loop;
	u_int32_t h;

#define HASHC   h = *key++ + 65599 * h

	h = 0;
	key = keyarg;
	if (len > 0) {
		loop = (len + 8 - 1) >> 3;

		switch (len & (8 - 1)) {
		case 0:
			do {
				HASHC;
				/* FALLTHROUGH */
		case 7:
				HASHC;
				/* FALLTHROUGH */
		case 6:
				HASHC;
				/* FALLTHROUGH */
		case 5:
				HASHC;
				/* FALLTHROUGH */
		case 4:
				HASHC;
				/* FALLTHROUGH */
		case 3:
				HASHC;
				/* FALLTHROUGH */
		case 2:
				HASHC;
				/* FALLTHROUGH */
		case 1:
				HASHC;
			} while (--loop);
		}
	}
	return (h);
}

/*
 * Generate a hash value for a given key (character string).
 * We mask off all but the lower 8 bits since our table array
 * can only hold 256 elements.
 */
u_int32_t
hashkey(char *key)
{

	if (key == NULL)
		return (-1);
	return(hash((void *)key, strlen(key)) & HASH_MASK);
}

/* Find an entry in the hash table (may be hanging off a linked list). */
char *
lookup(struct group_entry *table[], char *key)
{
	struct group_entry *cur;

	cur = table[hashkey(key)];

	while (cur) {
		if (!strcmp(cur->key, key))
			return(cur->data);
		cur = cur->next;
	}

	return(NULL);
}

/*
 * Store an entry in the main netgroup hash table. Here's how this
 * works: the table can only be so big when we initialize it (TABLESIZE)
 * but the number of netgroups in the /etc/netgroup file could easily be
 * much larger than the table. Since our hash values are adjusted to
 * never be greater than TABLESIZE too, this means it won't be long before
 * we find ourselves with two keys that hash to the same value.
 *
 * One way to deal with this is to malloc(2) a second table and start
 * doing indirection, but this is a pain in the butt and it's not worth
 * going to all that trouble for a dinky little program like this. Instead,
 * we turn each table entry into a linked list and simply link keys
 * with the same hash value together at the same index location within
 * the table.
 *
 * That's a lot of comment for such a small piece of code, isn't it.
 */
void
store(struct group_entry *table[], char *key, char *data)
{
	struct group_entry *new;
	u_int32_t i;

	i = hashkey(key);

	new = (struct group_entry *)malloc(sizeof(struct group_entry));
	new->key = strdup(key);
	new->data = strdup(data);
	new->next = table[i];
	table[i] = new;

	return;
}

/*
 * Store a group member entry and/or update its grouplist. This is
 * a bit more complicated than the previous function since we have to
 * maintain not only the hash table of group members, each group member
 * structure also has a linked list of groups hung off it. If handed
 * a member name that we haven't encountered before, we have to do
 * two things: add that member to the table (possibly hanging them
 * off the end of a linked list, as above), and add a group name to
 * the member's grouplist list. If we're handed a name that already has
 * an entry in the table, then we just have to do one thing, which is
 * to update its grouplist.
 */
void
mstore(struct member_entry *table[], char *key, char *data, char *domain)
{
	struct member_entry *cur, *new;
	struct grouplist *tmp;
	u_int32_t i;

	i = hashkey(key);
	cur = table[i];

	tmp = (struct grouplist *)malloc(sizeof(struct grouplist));
	tmp->groupname = strdup(data);
	tmp->next = NULL;

	/* Check if all we have to do is insert a new groupname. */
	while (cur) {
		if (!strcmp(cur->key, key)) {
			tmp->next = cur->groups;
			cur->groups = tmp;
			return;
		}
		cur = cur->next;
	}

	/* Didn't find a match -- add the whole mess to the table. */
	new = (struct member_entry *)malloc(sizeof(struct member_entry));
	new->key = strdup(key);
	new->domain = domain ? strdup(domain) : "*";
	new->groups = tmp;
	new->next = table[i];
	table[i] = new;

	return;
}