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gmcninch-tufts
GitHub Repository: gmcninch-tufts/2024-Sp-Math190
Path: blob/main/course-assignments/PS01--rep-theory.md
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title: | ProblemSet 1 -- Linear algebra and representations author: George McNinch date: 2024-01-29
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FF denotes an algebraically closed field of characteristic 0. If you like, you can suppose that F=CF = \mathbf{C} is the field of complex numbers.

  1. Let VV be a finite dimensional vector space over the field FF. Suppose that ϕ,ψ:VV\phi,\psi:V \to V are linear maps. Let λF\lambda \in F be an eigenvalue of ϕ\phi and write WW for the λ\lambda-eigenspace of ϕ\phi; i.e. W={vVϕ(v)=λv}.W = \{v \in V \mid \phi(v) = \lambda v \}. If ϕψ=ψϕ\phi \psi = \psi \phi show that WW is invariant under ψ\psi -- i.e. show that ψ(W)W\psi(W) \subseteq W.

  2. Let nNn \in \mathbf{N} be a non-zero natural number, and let VV be an nn dimensional FF-vector space with a given basis e1,e2,,ene_1,e_2,\cdots,e_n.

    Consider the linear transformation T:VVT:V \to V given by the rule Tei=ei+1(modn).Te_i = e_{i+1 \pmod n}. In other words Tei={ei+1i<ne1i=n.Te_i = \left \{ \begin{matrix} e_{i+1} & i < n \\ e_1 & i =n \end{matrix} \right ..

    a. Show that TT is invertible and that Tn=idVT^n = \operatorname{id}_V.

    b. Consider the vector v0=i=1neiv_0 = \displaystyle \sum_{i=1}^n e_i. Show that v0v_0 is a 11-eigenvector for TT.

    Let ζF\zeta \in F be a primitive nn-th root of unity. (e.g. if you assume F=CF = \mathbf{C}, you may as well take ζ=e2πi/n\zeta = e^{2\pi i/n}).

    c. Let v1=i=1nζieiv_1 = \displaystyle \sum_{i=1}^n \zeta^i e_i. Show that v1v_1 is a ζ1\zeta^{-1}-eigenvector for TT.

    d. More generally, let 0j<n0 \le j < n and let vj=i=1nζijei.v_j = \sum_{i=1}^n \zeta^{ij} e_i. Show that vjv_j is a ζj\zeta^{-j}-eigenvector for TT.

    e. Conclude that v0,v1,,vn1v_0,v_1,\cdots,v_{n-1} is a basis of VV consisting of eigenvectors for TT, so that TT is diagonalizable.

    Hint: You need to use the fact that eigenvectors for distinct eigenvalues are linearly independent.

    What is the matrix of TT in this basis?

  3. Let G=Z/3ZG = \mathbb{Z}/3\mathbb{Z} be the additive group of order 33, and let ζ\zeta be a primitive 33rd root of unity in FF.

    To define a representation ρ:GGLn(F)\rho:G \to \operatorname{GL}_n(F), it is enough to find a matrix MGLn(F)M \in \operatorname{GL}_n(F) with M3=1M^3 = 1; in turn, MM determines a representation ρ\rho by the rule ρ(i+3Z)=Mi\rho(i + 3\mathbb{Z}) = M^i.

    Consider the representation ρ1:GGL3(F)\rho_1 : G \to \operatorname{GL}_3(F) given by the matrix ρ1(1+3Z)=M1=[1000ζ000ζ2]\rho_1(1 + 3\mathbb{Z}) = M_1 = \begin{bmatrix} 1 & 0 & 0\\ 0 & \zeta & 0 \\ 0 & 0 & \zeta^2 \end{bmatrix} and consider the representation ρ2:GGL3(F)\rho_2:G \to \operatorname{GL}_3(F) given by the matrix ρ2(1+3Z)=M2=[001100010].\rho_2(1 + 3\mathbb{Z}) = M_2 = \begin{bmatrix} 0 & 0 & 1\\ 1 & 0 & 0 \\ 0 & 1 & 0 \end{bmatrix}.

    Show that the representations ρ1\rho_1 and ρ2\rho_2 are equivalent (alternative terminology: are isomorphic). In other words, find a linear bijection Φ:F3F3\Phi:F^3 \to F^3 with the property that Φ(ρ2(g)v)=ρ1(g)Φ(v)\Phi(\rho_2(g)v) = \rho_1(g)\Phi(v) for every gGg \in G and vF3v \in F^3.

    Hint: First find a basis of F3F^3 consisting of eigenvectors for the matrix M2M_2.

  4. Let VV be a nn dimensional FF-vector space for nNn \in \mathbb{N}.

    Let GL(V)\operatorname{GL}(V) denote the group $$\operatorname{GL}(V) = \{ \text{all invertible $Flineartransformations-linear transformations \phi:V \to VParseError: KaTeX parse error: Expected 'EOF', got '}' at position 1: }̲\}$ where the group operation is composition of linear transformations.

    Recall that GLn(F)\operatorname{GL}_n(F) denotes the group of all invertible n×nn \times n matrices.

    If B={b1,b2,,bn}\mathcal{B} = \{b_1,b_2,\cdots,b_n\} is a choice of basis, show that the assignment ϕ[ϕ]B\phi \mapsto [\phi]_{\mathcal{B}} determines an isomorphism GL(V)GLn(F).\operatorname{GL}(V) \xrightarrow{\sim} \operatorname{GL}_n(F).

    Here [ϕ]B=[Mij][\phi]_{\mathcal{B}} = [M_{ij}] denotes the matrix of ϕ\phi in the basis B\mathcal{B} defined by equations

    ϕ(bi)=k=1nMkibk.\phi(b_i) = \sum_{k=1}^n M_{ki} b_k.