# This sample tests that the type checker handles the case# where a symbol within a class scope is assigned an expression# that includes the same symbol, but that same symbol is defined# in an outer scope.a=0b=1c=4classMyClass:# This should not generate an error because# the RHS of the assignment refers to a different# "a", declared in an outer scope.a=a# Same with "b" here.(b,a)=(b,3)# Same with "c" here.[c]=[c]# This should generate an error because "d" is# not declared in the outer scope.e=d