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ubuntu2004
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<exercise checkit-seed="0007" checkit-slug="AA1" checkit-title="Structure of an IVP and Verifying Solutions">
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<statement>
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<p>
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For each of the following Initial Value Problems (IVPs), designate the following:
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</p>
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<ul>
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<li>its Ordinary Differential Equation (ODE)</li>
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<li>its Initial Value or Values (IVs)</li>
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<li>the order of the IVP</li>
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<li>its independent variable</li>
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<li>its dependent variable</li>
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<li>whether its solution is implicit or explicit</li>
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</ul>
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<p>
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Then show how to verify that its solution is valid.
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</p>
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<ol>
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<li>
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<ul>
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<li>IVP:
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<m>
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4 \, y^{3} {y'} - 3 \, x {y'} = 3 \, y;\qquad
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y(-1)=
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1 </m>
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</li>
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<li>Solution: <m>y^{4} - 3 \, x y = 4</m></li>
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</ul>
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</li>
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<li>
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<ul>
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<li>IVP:
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<m>
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-3 \, y + 4 \, {\frac{dy}{dt}} - {\frac{d^2y}{dt^2}} = 0;\qquad
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y(0)=
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1,
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y'(0)=
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1
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</m>
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</li>
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<li>Solution: <m>y = e^{t}</m></li>
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</ul>
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</li>
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<li>
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<ul>
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<li>IVP:
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<m>
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2 \, t^{3} + 4 \, y = t {y'};\qquad
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y(1)=
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-6 </m>
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</li>
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<li>Solution: <m>y = -4 \, t^{4} - 2 \, t^{3}</m></li>
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</ul>
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</li>
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</ol>
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</statement>
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<answer>
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<ol>
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<li>
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<ul>
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<li>ODE: <m>4 \, y^{3} {y'} - 3 \, x {y'} = 3 \, y</m></li>
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<li>IV(s): <m>
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y(-1)=1
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</m></li>
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<li>Order: 1st</li>
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<li>Independent variable: <m>x</m></li>
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<li>Dependent variable: <m>y</m></li>
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<li>The solution <m>y^{4} - 3 \, x y = 4</m> is implicit.</li>
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</ul>
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</li>
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<li>
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<ul>
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<li>ODE: <m>-3 \, y + 4 \, {\frac{dy}{dt}} - {\frac{d^2y}{dt^2}} = 0</m></li>
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<li>IV(s): <m>
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y(0)=1
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,y'(0)=1
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</m></li>
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<li>Order: 2nd</li>
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<li>Independent variable: <m>t</m></li>
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<li>Dependent variable: <m>y</m></li>
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<li>The solution <m>y = e^{t}</m> is explicit.</li>
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</ul>
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</li>
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<li>
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<ul>
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<li>ODE: <m>2 \, t^{3} + 4 \, y = t {y'}</m></li>
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<li>IV(s): <m>
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y(1)=-6
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</m></li>
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<li>Order: 1st</li>
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<li>Independent variable: <m>t</m></li>
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<li>Dependent variable: <m>y</m></li>
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<li>The solution <m>y = -4 \, t^{4} - 2 \, t^{3}</m> is explicit.</li>
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</ul>
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</li>
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</ol>
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</answer>
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</exercise>
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