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\documentclass{exam}
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\usepackage{hyperref}
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\usepackage{amsmath}
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\usepackage{amsfonts}
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\printanswers
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\begin{document}
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\begin{center}
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Worksheet 6 - Due 11/10
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\end{center}
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\begin{questions}
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\question
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You should be familiar with the theorem here: \url{http://kevinlui.org/au17m308/log/4-review.html}
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\begin{parts}
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\part
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There is a somewhat obvious error. Find it.
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\begin{solution}
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It turns out there are (at least?) 2 errors.
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\begin{itemize}
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\item
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``Let $A=[a_1,\ldots,a_m]$ be a matrix...'' The matrix
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$A$ is of the wrong dimension.
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\item
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``number of rows of all zeros in $B$.'' This is the
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nullity of $A$ instead of the null space.
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\end{itemize}
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\end{solution}
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\part
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Write down all the different ways to express the nullity.
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\begin{solution}
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Here we use the same set up as in here: http://kevinlui.org/au17m308/log/4-review.html
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\begin{itemize}
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\item
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$nullity(A)$
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\item
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$dim(null(A))$
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\item
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$nullity(B)$
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\item
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$dim(null(B))$
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\item
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$dim(ker(T))$
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\item
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number of free variables in $B$
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\item
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$m-rank(A)$
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\item
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number of vectors required to span the solution space
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of $Ax=0$.
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\end{itemize}
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\end{solution}
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\end{parts}
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\question
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What is the absolute value of the determinant of the matrix in problem 2 of
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worksheet 5?
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\begin{solution}
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The matrix in question defines a reflection across some plane. This
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preserves volume so the absolute value of the determinant should be 1.
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\end{solution}
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\end{questions}
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\end{document}
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