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ubuntu2004
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<exercise checkit-seed="0007" checkit-slug="V2" checkit-title="Linear combinations">
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<statement>
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<p>Consider the following statement.</p>
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<ul>
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<li>
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The vector <m> \left[\begin{array}{c}
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8 \\
8
5 \\
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-11 \\
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11
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\end{array}\right] </m>is
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a linear combination of the vectors <m> \left[\begin{array}{c}
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0 \\
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1 \\
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3 \\
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-1
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\end{array}\right] , \left[\begin{array}{c}
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3 \\
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1 \\
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-2 \\
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1
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\end{array}\right] , \left[\begin{array}{c}
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-1 \\
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-3 \\
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-1 \\
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-3
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\end{array}\right] , \left[\begin{array}{c}
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1 \\
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-2 \\
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-2 \\
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0
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\end{array}\right] , \text{ and } \left[\begin{array}{c}
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4 \\
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-1 \\
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2 \\
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1
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\end{array}\right] </m>.
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</li>
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</ul>
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<ol>
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<li> Write an equivalent statement using a vector equation.</li>
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<li> Explain why your statement is true or false.</li>
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</ol>
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</statement>
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<answer>
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<me>\operatorname{RREF} \left[\begin{array}{ccccc|c}
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0 &amp; 3 &amp; -1 &amp; 1 &amp; 4 &amp; 8 \\
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1 &amp; 1 &amp; -3 &amp; -2 &amp; -1 &amp; 5 \\
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3 &amp; -2 &amp; -1 &amp; -2 &amp; 2 &amp; -11 \\
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-1 &amp; 1 &amp; -3 &amp; 0 &amp; 1 &amp; 11
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\end{array}\right] = \left[\begin{array}{ccccc|c}
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1 &amp; 0 &amp; 0 &amp; 0 &amp; \frac{12}{5} &amp; -3 \\
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0 &amp; 1 &amp; 0 &amp; 0 &amp; -\frac{1}{5} &amp; 2 \\
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0 &amp; 0 &amp; 1 &amp; 0 &amp; -\frac{6}{5} &amp; -2 \\
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0 &amp; 0 &amp; 0 &amp; 1 &amp; \frac{17}{5} &amp; 0
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\end{array}\right] </me>
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<ol>
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<li>
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The vector equation <m> x_{1} \left[\begin{array}{c}
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0 \\
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1 \\
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3 \\
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-1
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\end{array}\right] + x_{2} \left[\begin{array}{c}
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3 \\
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1 \\
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-2 \\
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1
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\end{array}\right] + x_{3} \left[\begin{array}{c}
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-1 \\
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-3 \\
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-1 \\
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-3
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\end{array}\right] + x_{4} \left[\begin{array}{c}
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1 \\
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-2 \\
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-2 \\
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0
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\end{array}\right] + x_{5} \left[\begin{array}{c}
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4 \\
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-1 \\
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2 \\
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1
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\end{array}\right] = \left[\begin{array}{c}
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8 \\
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5 \\
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-11 \\
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11
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\end{array}\right] </m>has a solution.</li>
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<li>
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<p><m> \left[\begin{array}{c}
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8 \\
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5 \\
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-11 \\
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11
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\end{array}\right] </m> is
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a linear combination of the vectors <m> \left[\begin{array}{c}
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0 \\
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1 \\
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3 \\
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-1
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\end{array}\right] , \left[\begin{array}{c}
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3 \\
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1 \\
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-2 \\
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1
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\end{array}\right] , \left[\begin{array}{c}
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-1 \\
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-3 \\
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-1 \\
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-3
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\end{array}\right] , \left[\begin{array}{c}
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1 \\
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-2 \\
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-2 \\
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0
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\end{array}\right] , \text{ and } \left[\begin{array}{c}
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4 \\
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-1 \\
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2 \\
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1
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\end{array}\right] </m>.
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</p>
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</li>
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</ol>
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</answer>
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</exercise>
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