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\begin{exerciseStatement}
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Find the solution to the given IVP.
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\[ -2 \, {y}^{2} {y'} = -\frac{4 \, t}{{y}} - \frac{4}{{y}} \hspace{2em}
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y( 3 )= 3 \]
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\end{exerciseStatement}
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\begin{exerciseAnswer}
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\[ {y} = {\left(t^{2} + 2 \, t + 12\right)}^{\frac{1}{3}} \]
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\end{exerciseAnswer}
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