<item ident="F3-2171" title="F3 | Techniques for linear IVPs | ver. 2171">
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<strong>F3.</strong>
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<p>Find the solution to the given IVP.</p>
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<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0" alt="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0" title="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0" data-latex="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0"/>
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<p>
<strong>F3.</strong>
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<p>Find the solution to the given IVP.</p>
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<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-3%20%5C,%20%7By%7D%20-%20%5Cfrac%7B4%7D%7Bt%7D%20=%20-%7By'%7D%20t%20%5Chspace%7B2em%7D%20y(%20-1%20)=%200" alt="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0" title="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0" data-latex="-3 \, {y} - \frac{4}{t} = -{y'} t \hspace{2em} y( -1 )= 0">
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<h4>Partial Answer:</h4>
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<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?{y} = t^{3} - \frac{1}{t}" alt="{y} = t^{3} - \frac{1}{t}" title="{y} = t^{3} - \frac{1}{t}" data-latex="{y} = t^{3} - \frac{1}{t}"/>
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<h4>Partial Answer:</h4>
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<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?%7By%7D%20=%20t%5E%7B3%7D%20-%20%5Cfrac%7B1%7D%7Bt%7D" alt="{y} = t^{3} - \frac{1}{t}" title="{y} = t^{3} - \frac{1}{t}" data-latex="{y} = t^{3} - \frac{1}{t}">
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