0008.qti

<item ident="F4-6005" title="F4 | Implicit solutions for exact IVPs | ver. 6005">
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  <presentation>
    <material>
      <mattextxml>
        <div class="exercise-statement">
          <p>
            <strong>F4.</strong>
          </p>
          <p> Determine which of the following ODEs is exact. </p>
          <p style="text-align:center;">
            <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" alt="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" title="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" data-latex="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}"/>
          </p>
          <p style="text-align:center;">
            <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}" alt="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}" title="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}" data-latex="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}"/>
          </p>
          <p> Then find an implicit solution for this exact ODE satisfying the initial value <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?y( -1 )= 1" alt="y( -1 )= 1" title="y( -1 )= 1" data-latex="y( -1 )= 1"/>. </p>
        </div>
      </mattextxml>
      <mattext texttype="text/html">&lt;div class="exercise-statement"&gt;
  &lt;p&gt;
    &lt;strong&gt;F4.&lt;/strong&gt;
  &lt;/p&gt;
  &lt;p&gt; Determine which of the following ODEs is exact. &lt;/p&gt;
  &lt;p style="text-align:center;"&gt;
    &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?5%20%5C,%20y%5E%7B2%7D%20-%20t%20%7By'%7D%20-%20y%20=%20-10%20%5C,%20t%20y%20%7By'%7D%20+%206%20%5C,%20y%5E%7B2%7D%20%7By'%7D" alt="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" title="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" data-latex="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}"&gt;
  &lt;/p&gt;
  &lt;p style="text-align:center;"&gt;
    &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-6%20%5C,%20t%5E%7B2%7D%20y%20%7By'%7D%20+%206%20%5C,%20t%20y%20-%20y%20=%206%20%5C,%20y%5E%7B2%7D%20%7By'%7D%20-%205%20%5C,%20y%5E%7B2%7D" alt="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}" title="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}" data-latex="-6 \, t^{2} y {y'} + 6 \, t y - y = 6 \, y^{2} {y'} - 5 \, y^{2}"&gt;
  &lt;/p&gt;
  &lt;p&gt; Then find an implicit solution for this exact ODE satisfying the initial value &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?y(%20-1%20)=%201" alt="y( -1 )= 1" title="y( -1 )= 1" data-latex="y( -1 )= 1"&gt;. &lt;/p&gt;
&lt;/div&gt;

</mattext>
    </material>
    <response_str ident="response1" rcardinality="Single">
      <render_fib>
        <response_label ident="answer1" rshuffle="No"/>
      </render_fib>
    </response_str>
  </presentation>
  <itemfeedback ident="general_fb">
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      <material>
        <mattextxml>
          <div class="exercise-answer">
            <h4>Partial Answer:</h4>
            <p>The following ODE is exact.</p>
            <p style="text-align:center;">
              <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" alt="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" title="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" data-latex="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}"/>
            </p>
            <p> Its implicit solution satisfying the initial value is: </p>
            <p style="text-align:center;">
              <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-5 \, t y^{2} + 2 \, y^{3} + t y = 6" alt="-5 \, t y^{2} + 2 \, y^{3} + t y = 6" title="-5 \, t y^{2} + 2 \, y^{3} + t y = 6" data-latex="-5 \, t y^{2} + 2 \, y^{3} + t y = 6"/>
            </p>
          </div>
        </mattextxml>
        <mattext texttype="text/html">&lt;div class="exercise-answer"&gt;
  &lt;h4&gt;Partial Answer:&lt;/h4&gt;
  &lt;p&gt;The following ODE is exact.&lt;/p&gt;
  &lt;p style="text-align:center;"&gt;
    &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?5%20%5C,%20y%5E%7B2%7D%20-%20t%20%7By'%7D%20-%20y%20=%20-10%20%5C,%20t%20y%20%7By'%7D%20+%206%20%5C,%20y%5E%7B2%7D%20%7By'%7D" alt="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" title="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}" data-latex="5 \, y^{2} - t {y'} - y = -10 \, t y {y'} + 6 \, y^{2} {y'}"&gt;
  &lt;/p&gt;
  &lt;p&gt; Its implicit solution satisfying the initial value is: &lt;/p&gt;
  &lt;p style="text-align:center;"&gt;
    &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-5%20%5C,%20t%20y%5E%7B2%7D%20+%202%20%5C,%20y%5E%7B3%7D%20+%20t%20y%20=%206" alt="-5 \, t y^{2} + 2 \, y^{3} + t y = 6" title="-5 \, t y^{2} + 2 \, y^{3} + t y = 6" data-latex="-5 \, t y^{2} + 2 \, y^{3} + t y = 6"&gt;
  &lt;/p&gt;
&lt;/div&gt;

</mattext>
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