<item ident="F5-0946" title="F5 | Substitution strategies | ver. 0946"> <itemmetadata> <qtimetadata> <qtimetadatafield> <fieldlabel>question_type</fieldlabel> <fieldentry>essay_question</fieldentry> </qtimetadatafield> </qtimetadata> </itemmetadata> <presentation> <material> <mattextxml> <div class="exercise-statement"> <p> <strong>F5.</strong> </p> <p> Apply each of the substitutions <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=\frac{y}{t}" alt="u=\frac{y}{t}" title="u=\frac{y}{t}" data-latex="u=\frac{y}{t}"/> and <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=at+by+c" alt="u=at+by+c" title="u=at+by+c" data-latex="u=at+by+c"/> to one of the following ODEs, and show that each result is separable. (Do not fully solve either ODE.) </p> <ol type="a"> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-t - y + {y'} = -\frac{2}{t + y + 2} + 3" alt="-t - y + {y'} = -\frac{2}{t + y + 2} + 3" title="-t - y + {y'} = -\frac{2}{t + y + 2} + 3" data-latex="-t - y + {y'} = -\frac{2}{t + y + 2} + 3"/> </li> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?t y {y'} - 4 \, t^{2} + y^{2} = 0" alt="t y {y'} - 4 \, t^{2} + y^{2} = 0" title="t y {y'} - 4 \, t^{2} + y^{2} = 0" data-latex="t y {y'} - 4 \, t^{2} + y^{2} = 0"/> </li> </ol> </div> </mattextxml> <mattext texttype="text/html"><div class="exercise-statement"> <p> <strong>F5.</strong> </p> <p> Apply each of the substitutions <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=%5Cfrac%7By%7D%7Bt%7D" alt="u=\frac{y}{t}" title="u=\frac{y}{t}" data-latex="u=\frac{y}{t}"> and <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=at+by+c" alt="u=at+by+c" title="u=at+by+c" data-latex="u=at+by+c"> to one of the following ODEs, and show that each result is separable. (Do not fully solve either ODE.) </p> <ol type="a"> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-t%20-%20y%20+%20%7By'%7D%20=%20-%5Cfrac%7B2%7D%7Bt%20+%20y%20+%202%7D%20+%203" alt="-t - y + {y'} = -\frac{2}{t + y + 2} + 3" title="-t - y + {y'} = -\frac{2}{t + y + 2} + 3" data-latex="-t - y + {y'} = -\frac{2}{t + y + 2} + 3"> </li> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?t%20y%20%7By'%7D%20-%204%20%5C,%20t%5E%7B2%7D%20+%20y%5E%7B2%7D%20=%200" alt="t y {y'} - 4 \, t^{2} + y^{2} = 0" title="t y {y'} - 4 \, t^{2} + y^{2} = 0" data-latex="t y {y'} - 4 \, t^{2} + y^{2} = 0"> </li> </ol> </div> </mattext> </material> <response_str ident="response1" rcardinality="Single"> <render_fib> <response_label ident="answer1" rshuffle="No"/> </render_fib> </response_str> </presentation> <itemfeedback ident="general_fb"> <flow_mat> <material> <mattextxml> <div class="exercise-answer"> <h4>Partial Answer:</h4> <ol type="a"> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?\frac{u {u'}}{u^{2} - 2} = 1" alt="\frac{u {u'}}{u^{2} - 2} = 1" title="\frac{u {u'}}{u^{2} - 2} = 1" data-latex="\frac{u {u'}}{u^{2} - 2} = 1"/> </li> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}" alt="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}" title="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}" data-latex="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}"/> </li> </ol> </div> </mattextxml> <mattext texttype="text/html"><div class="exercise-answer"> <h4>Partial Answer:</h4> <ol type="a"> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?%5Cfrac%7Bu%20%7Bu'%7D%7D%7Bu%5E%7B2%7D%20-%202%7D%20=%201" alt="\frac{u {u'}}{u^{2} - 2} = 1" title="\frac{u {u'}}{u^{2} - 2} = 1" data-latex="\frac{u {u'}}{u^{2} - 2} = 1"> </li> <li> <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?%5Cfrac%7Bu%20%7Bu'%7D%7D%7Bu%5E%7B2%7D%20-%204%7D%20=%20%5Cfrac%7B1%7D%7Bt%7D" alt="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}" title="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}" data-latex="\frac{u {u'}}{u^{2} - 4} = \frac{1}{t}"> </li> </ol> </div> </mattext> </material> </flow_mat> </itemfeedback> </item>