<item ident="X3-9588" title="X3 | Existence/uniqueness theorem for first-order IVPs | ver. 9588">
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<p>
<strong>X3.</strong>
</p>
<p> Explain what the Existence and Uniqueness Theorem for First Order IVPs guarantees about the existence and uniqueness of solutions for the following IVP. </p>
<p style="text-align:center;">
<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3" alt="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3" title="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3" data-latex="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3"/>
</p>
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<mattext texttype="text/html"><div class="exercise-statement">
<p>
<strong>X3.</strong>
</p>
<p> Explain what the Existence and Uniqueness Theorem for First Order IVPs guarantees about the existence and uniqueness of solutions for the following IVP. </p>
<p style="text-align:center;">
<img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?y'=%205%20%5C,%20%7B%5Cleft(2%20%5C,%20%7By%7D%20+%202%20%5C,%20t%20+%206%5Cright)%7D%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%5Chspace%7B2em%7D%20x(%20-6%20)=%203" alt="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3" title="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3" data-latex="y'= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}} \hspace{2em} x( -6 )= 3">
</p>
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<response_str ident="response1" rcardinality="Single">
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<h4>Partial Answer:</h4>
<p><img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}" alt="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}" title="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}" data-latex="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}"/> is continuous at and nearby the initial value so a solution exists for a nearby interval. </p>
<p><img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}" alt="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}" title="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}" data-latex="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}"/> is continous at and nearby the initial value so the solution is unique for a nearby interval. </p>
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<mattext texttype="text/html"><div class="exercise-answer">
<h4>Partial Answer:</h4>
<p><img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?F(t,y)=%205%20%5C,%20%7B%5Cleft(2%20%5C,%20%7By%7D%20+%202%20%5C,%20t%20+%206%5Cright)%7D%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D" alt="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}" title="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}" data-latex="F(t,y)= 5 \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{4}{3}}"> is continuous at and nearby the initial value so a solution exists for a nearby interval. </p>
<p><img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?F_y=%20%5Cfrac%7B40%7D%7B3%7D%20%5C,%20%7B%5Cleft(2%20%5C,%20%7By%7D%20+%202%20%5C,%20t%20+%206%5Cright)%7D%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D" alt="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}" title="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}" data-latex="F_y= \frac{40}{3} \, {\left(2 \, {y} + 2 \, t + 6\right)}^{\frac{1}{3}}"> is continous at and nearby the initial value so the solution is unique for a nearby interval. </p>
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