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y = \sin^{-1}{\cos{x}} \\ \dfrac{dy}{dx} = \dfrac{-\sin{x}}{\sqrt{1-\cos^{2}{x}}} \\ \dfrac{dy}{dx} = \dfrac{-\sin{x}}{\sqrt{\sin^{2}{x}}}\\ \dfrac{dy}{dx} = \dfrac{-\sin{x}}{\sin{x}}\\ \dfrac{dy}{dx} = -1
