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GEP475GROUPINEEDANAP

Views: 1461
Kernel: Python 2 (SageMath)
import pandas as pd import numpy as nb
netatmo = pd.read_csv('NetAtmo_2016.csv', parse_dates=True, index_col=1)
netatmo['time']= netatmo.index netatmo['time'].diff(1)
Timezone : America/Los_Angeles 2016-02-19 13:26:00 NaT 2016-02-19 13:27:00 00:01:00 2016-02-19 13:27:00 00:00:00 2016-02-19 13:31:00 00:04:00 2016-02-19 13:36:00 00:05:00 2016-02-19 13:41:00 00:05:00 2016-02-19 13:46:00 00:05:00 2016-02-19 13:51:00 00:05:00 2016-02-19 13:56:00 00:05:00 2016-02-19 14:02:00 00:06:00 2016-02-19 14:07:00 00:05:00 2016-02-19 14:12:00 00:05:00 2016-02-19 14:17:00 00:05:00 2016-02-19 14:22:00 00:05:00 2016-02-19 14:27:00 00:05:00 2016-02-19 14:32:00 00:05:00 2016-02-19 14:37:00 00:05:00 2016-02-19 14:42:00 00:05:00 2016-02-19 14:47:00 00:05:00 2016-02-19 14:52:00 00:05:00 2016-02-19 14:57:00 00:05:00 2016-02-19 15:02:00 00:05:00 2016-02-19 15:07:00 00:05:00 2016-02-19 15:12:00 00:05:00 2016-02-19 15:17:00 00:05:00 2016-02-19 15:22:00 00:05:00 2016-02-19 15:27:00 00:05:00 2016-02-19 15:32:00 00:05:00 2016-02-19 15:37:00 00:05:00 2016-02-19 15:42:00 00:05:00 ... 2016-12-31 21:30:00 00:06:00 2016-12-31 21:35:00 00:05:00 2016-12-31 21:40:00 00:05:00 2016-12-31 21:45:00 00:05:00 2016-12-31 21:50:00 00:05:00 2016-12-31 21:55:00 00:05:00 2016-12-31 22:00:00 00:05:00 2016-12-31 22:05:00 00:05:00 2016-12-31 22:10:00 00:05:00 2016-12-31 22:15:00 00:05:00 2016-12-31 22:20:00 00:05:00 2016-12-31 22:25:00 00:05:00 2016-12-31 22:30:00 00:05:00 2016-12-31 22:35:00 00:05:00 2016-12-31 22:40:00 00:05:00 2016-12-31 22:45:00 00:05:00 2016-12-31 22:50:00 00:05:00 2016-12-31 22:55:00 00:05:00 2016-12-31 23:00:00 00:05:00 2016-12-31 23:05:00 00:05:00 2016-12-31 23:10:00 00:05:00 2016-12-31 23:15:00 00:05:00 2016-12-31 23:20:00 00:05:00 2016-12-31 23:25:00 00:05:00 2016-12-31 23:30:00 00:05:00 2016-12-31 23:35:00 00:05:00 2016-12-31 23:40:00 00:05:00 2016-12-31 23:45:00 00:05:00 2016-12-31 23:50:00 00:05:00 2016-12-31 23:55:00 00:05:00 Name: time, dtype: timedelta64[ns]
netatmo['time'].diff(1).sum()
Timedelta('316 days 10:29:00')
netatmo['time'].diff(1).sum() / nb.timedelta64(1, 'h')
7594.4833333333336