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ubuntu2004
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<exercise checkit-seed="0001" checkit-slug="V2" checkit-title="Linear combinations">
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<statement>
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<p>Consider the following statement.</p>
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<ul>
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<li>
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The vector <m> \left[\begin{array}{c}
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-6 \\
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1 \\
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7 \\
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-2
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\end{array}\right] </m>is not
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a linear combination of the vectors <m> \left[\begin{array}{c}
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4 \\
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-2 \\
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1 \\
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0
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\end{array}\right] , \left[\begin{array}{c}
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-5 \\
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0 \\
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4 \\
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-3
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\end{array}\right] , \left[\begin{array}{c}
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-3 \\
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1 \\
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-4 \\
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-1
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\end{array}\right] , \text{ and } \left[\begin{array}{c}
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-2 \\
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-2 \\
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2 \\
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-2
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\end{array}\right] </m>.
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</li>
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</ul>
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<ol>
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<li> Write an equivalent statement using a vector equation.</li>
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<li> Explain why your statement is true or false.</li>
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</ol>
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</statement>
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<answer>
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<me>\operatorname{RREF} \left[\begin{array}{cccc|c}
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4 &amp; -5 &amp; -3 &amp; -2 &amp; -6 \\
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-2 &amp; 0 &amp; 1 &amp; -2 &amp; 1 \\
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1 &amp; 4 &amp; -4 &amp; 2 &amp; 7 \\
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0 &amp; -3 &amp; -1 &amp; -2 &amp; -2
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\end{array}\right] = \left[\begin{array}{cccc|c}
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1 &amp; 0 &amp; 0 &amp; 0 &amp; -1 \\
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0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\
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0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 \\
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0 &amp; 0 &amp; 0 &amp; 1 &amp; 0
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\end{array}\right] </me>
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<ol>
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<li>
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The vector equation <m> x_{1} \left[\begin{array}{c}
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4 \\
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-2 \\
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1 \\
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0
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\end{array}\right] + x_{2} \left[\begin{array}{c}
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-5 \\
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0 \\
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4 \\
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-3
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\end{array}\right] + x_{3} \left[\begin{array}{c}
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-3 \\
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1 \\
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-4 \\
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-1
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\end{array}\right] + x_{4} \left[\begin{array}{c}
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-2 \\
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-2 \\
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2 \\
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-2
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\end{array}\right] = \left[\begin{array}{c}
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-6 \\
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1 \\
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7 \\
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-2
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\end{array}\right] </m>has no solutions.</li>
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<li>
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<p><m> \left[\begin{array}{c}
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-6 \\
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1 \\
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7 \\
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-2
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\end{array}\right] </m> is
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a linear combination of the vectors <m> \left[\begin{array}{c}
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4 \\
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-2 \\
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1 \\
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0
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\end{array}\right] , \left[\begin{array}{c}
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-5 \\
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0 \\
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4 \\
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-3
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\end{array}\right] , \left[\begin{array}{c}
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-3 \\
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1 \\
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-4 \\
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-1
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\end{array}\right] , \text{ and } \left[\begin{array}{c}
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-2 \\
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-2 \\
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2 \\
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-2
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\end{array}\right] </m>.
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</p>
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</li>
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</ol>
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</answer>
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</exercise>
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