Real-time collaboration for Jupyter Notebooks, Linux Terminals, LaTeX, VS Code, R IDE, and more,
all in one place. Commercial Alternative to JupyterHub.
Real-time collaboration for Jupyter Notebooks, Linux Terminals, LaTeX, VS Code, R IDE, and more,
all in one place. Commercial Alternative to JupyterHub.
| Download
Path: Bisection method.ipynb
Views: 256Image: ubuntu2004
Kernel: Python 3 (system-wide)
In this activity we have a given function f(x) = ln(x)-sin(x) in the interval (2,4). We need to use the bisection method to find the root of the function.
In [1]:
In [3]:
In [0]:
I do not know what to do exactly I tried to figure out the root using the code I can not find but I would guess that the root is 2.0454546 from what I see on my graphing calculator when I graph the function.
In [0]:
In [0]: