0008.qti

<item ident="F5-6868" title="F5 | Substitution strategies | ver. 6868">
  <itemmetadata>
    <qtimetadata>
      <qtimetadatafield>
        <fieldlabel>question_type</fieldlabel>
        <fieldentry>essay_question</fieldentry>
      </qtimetadatafield>
    </qtimetadata>
  </itemmetadata>
  <presentation>
    <material>
      <mattextxml>
        <div class="exercise-statement">
          <p>
            <strong>F5.</strong>
          </p>
          <p> Apply each of the substitutions <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=\frac{y}{t}" alt="u=\frac{y}{t}" title="u=\frac{y}{t}" data-latex="u=\frac{y}{t}"/> and <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=at+by+c" alt="u=at+by+c" title="u=at+by+c" data-latex="u=at+by+c"/> to one of the following ODEs, and show that each result is separable. (Do not fully solve either ODE.) </p>
          <ol type="a">
            <li>
              <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-5 \, t^{2} = t y {y'} + y^{2}" alt="-5 \, t^{2} = t y {y'} + y^{2}" title="-5 \, t^{2} = t y {y'} + y^{2}" data-latex="-5 \, t^{2} = t y {y'} + y^{2}"/>
            </li>
            <li>
              <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}" alt="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}" title="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}" data-latex="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}"/>
            </li>
          </ol>
        </div>
      </mattextxml>
      <mattext texttype="text/html">&lt;div class="exercise-statement"&gt;
  &lt;p&gt;
    &lt;strong&gt;F5.&lt;/strong&gt;
  &lt;/p&gt;
  &lt;p&gt; Apply each of the substitutions &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=%5Cfrac%7By%7D%7Bt%7D" alt="u=\frac{y}{t}" title="u=\frac{y}{t}" data-latex="u=\frac{y}{t}"&gt; and &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?u=at+by+c" alt="u=at+by+c" title="u=at+by+c" data-latex="u=at+by+c"&gt; to one of the following ODEs, and show that each result is separable. (Do not fully solve either ODE.) &lt;/p&gt;
  &lt;ol type="a"&gt;
    &lt;li&gt;
      &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-5%20%5C,%20t%5E%7B2%7D%20=%20t%20y%20%7By'%7D%20+%20y%5E%7B2%7D" alt="-5 \, t^{2} = t y {y'} + y^{2}" title="-5 \, t^{2} = t y {y'} + y^{2}" data-latex="-5 \, t^{2} = t y {y'} + y^{2}"&gt;
    &lt;/li&gt;
    &lt;li&gt;
      &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?-2%20%5C,%20t%20-%20%7By'%7D%20=%20-y%20-%20%5Cfrac%7B3%7D%7B2%20%5C,%20t%20-%20y%20-%202%7D" alt="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}" title="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}" data-latex="-2 \, t - {y'} = -y - \frac{3}{2 \, t - y - 2}"&gt;
    &lt;/li&gt;
  &lt;/ol&gt;
&lt;/div&gt;

</mattext>
    </material>
    <response_str ident="response1" rcardinality="Single">
      <render_fib>
        <response_label ident="answer1" rshuffle="No"/>
      </render_fib>
    </response_str>
  </presentation>
  <itemfeedback ident="general_fb">
    <flow_mat>
      <material>
        <mattextxml>
          <div class="exercise-answer">
            <h4>Partial Answer:</h4>
            <ol type="a">
              <li>
                <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}" alt="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}" title="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}" data-latex="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}"/>
              </li>
              <li>
                <img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?\frac{u {u'}}{u^{2} - 3} = 1" alt="\frac{u {u'}}{u^{2} - 3} = 1" title="\frac{u {u'}}{u^{2} - 3} = 1" data-latex="\frac{u {u'}}{u^{2} - 3} = 1"/>
              </li>
            </ol>
          </div>
        </mattextxml>
        <mattext texttype="text/html">&lt;div class="exercise-answer"&gt;
  &lt;h4&gt;Partial Answer:&lt;/h4&gt;
  &lt;ol type="a"&gt;
    &lt;li&gt;
      &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?%5Cfrac%7Bu%20%7Bu'%7D%7D%7Bu%5E%7B2%7D%20+%205%7D%20=%20%5Cfrac%7B1%7D%7Bt%7D" alt="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}" title="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}" data-latex="\frac{u {u'}}{u^{2} + 5} = \frac{1}{t}"&gt;
    &lt;/li&gt;
    &lt;li&gt;
      &lt;img style="border:1px #ddd solid;padding:5px;border-radius:5px;" src="https://latex.codecogs.com/svg.latex?%5Cfrac%7Bu%20%7Bu'%7D%7D%7Bu%5E%7B2%7D%20-%203%7D%20=%201" alt="\frac{u {u'}}{u^{2} - 3} = 1" title="\frac{u {u'}}{u^{2} - 3} = 1" data-latex="\frac{u {u'}}{u^{2} - 3} = 1"&gt;
    &lt;/li&gt;
  &lt;/ol&gt;
&lt;/div&gt;

</mattext>
      </material>
    </flow_mat>
  </itemfeedback>
</item>